Abstract
We will claim the velocity of the particles making up the CMB must be given by v_{cmb}=sqrt{k_bT_cmb/m_g}=c, where $k_b$ is the Boltzmann constant and T_cmb is the CMB temperature. This we will see leads to several interesting results such as the Hubble energy law: E_c=Nm_gv_cmb^2=Nm_gc^2=Nk_bT_cmb=T_p^3/T_0^2k_b/64 \pi^2. The findings here are fully consistent with the recent geometric mean approach of finding the CMB temperature by Haug and Tatum and also other related work we will refer to. }



![Author ORCID: We display the ORCID iD icon alongside authors names on our website to acknowledge that the ORCiD has been authenticated when entered by the user. To view the users ORCiD record click the icon. [opens in a new tab]](https://www.cambridge.org/engage/assets/public/coe/logo/orcid.png)