Abstract
The document presents a proof attempt for the Pythagorean Theorem, starting from the assumption that a right triangle with legs a and b and hypotenuse c might violate the relation π 2 = π 2 + π 2 . The author explores two cases: Assuming π 2 > π 2 + π 2 The document shows that this leads to contradictions with the triangle inequality π < π + π. Several algebraic decompositions of the excess term π are tested, each producing a contradiction such as π = π + π, which is impossible for a non-degenerate triangle. Assuming π 2 < π 2 + π 2 Similarly, this assumption leads to contradictions with the fact that the hypotenuse must be the longest side. Decompositions of the deficit term again produce impossible results such as π = π β π or π < π. Because both alternatives lead to contradictions, the document concludes that the only consistent possibility is: βπ 2 = π 2 + π 2β (from the document: β: c2 = a2 + b2 ... by A & Bβ) Thus, the proof uses proof by contradiction to establish the Pythagorean Theorem



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