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35 - Martin Gardner's Mistake

from VI - Cards and Probability

Michael Henle
Affiliation:
Oberlin College
Brian Hopkins
Affiliation:
Saint Peter's University
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Summary

Martin Gardner was amazingly accurate and reliable. That he made a mistake is simply testimonial to the difficulty of this particular problem, which appeared in 1959 and was republished in [3]:

Mr. Smith has two children. At least one of them is a boy. What is the probability that both children are boys?

Mr. Jones has two children. The older child is a girl. What is the probability that both children are girls?

Mr. Jones has failed to stir any controversy, so we ignore him and his two children [5]. Instead, we concentrate on Mr. Smith. Here is the solution that Martin Gardner published with the problem:

If Smith has two children, at least one of which is a boy, we have three equally probable cases: boy-boy, boy-girl, girl-boy. In only one case are both children boys, so the probability that both are boys is ⅓.

The corrected solution

Later Martin Gardner wrote a column titled “Probability and Ambiguity,” which was also republished (in [4]). In this column Gardner corrects himself, writing “… the answer depends on the procedure by which the information “at least one is a boy” is obtained.”

He suggested two potential procedures.

  • (i) Pick all the families with two children, one of which is a boy. If Mr. Smith is chosen randomly from this list, then the answer is ⅓.

  • […]

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    Publisher: Mathematical Association of America
    Print publication year: 2012

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