A planar set $G \subset {\bb R}^2$ is constructed that is bilipschitz equivalent to ($G, d^z$), where ($G, d$) is not bilipschitz embeddable to any uniformly convex Banach space. Here, $z \in (0, 1)$ and $d^z$ denotes the $z$th power of the metric $d$. This proves the existence of a strong $A_{\infty}$ weight in ${\bb R}^2$, such that the corresponding deformed geometry admits no bilipschitz mappings to any uniformly convex Banach space. Such a weight cannot be comparable to the Jacobian of a quasiconformal self-mapping of ${\bb R}^2$.