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The upper semilattice of degrees ≤ 0′ is complemented

Published online by Cambridge University Press:  12 March 2014

David B. Posner
David B. Posner*
Affiliation:
San Jose State University, San Jose, California 95192
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Extract

Let denote the set of degrees ≤ 0′. A degree a ≤ 0′ is said to be complemented in if there exists a degree b ≤ 0′ such that b ∪ a = 0′ and b ∩ a = 0. R.W. Robinson (cf. [11]) showed that every degree a ≤ 0′ satisfying a″ = 0″ is complemented in and the author [8] showed that every degree a ≤ 0′ satisfying a′ = 0″ is complemented in . Also, in [2], R. L. Epstein showed that every r.e. degree is complemented in . In this paper we will show that in fact every degree ≤ 0′ is complemented in . We will further show that the same is true in the upper semilattice of degrees ≤ c, where c is any complete degree. This is in contrast to the situation in the upper semilattice of r.e. degrees in which, as Lachlan [6] has shown, no degree other than 0 and 0′ is complemented.

Information

Type
Research Article
Information
The Journal of Symbolic Logic , Volume 46 , Issue 4 , December 1981 , pp. 705 - 713
Copyright
Copyright © Association for Symbolic Logic 1981

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References

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