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Unravelling the evolutionary advantage of sex: a commentary on ‘Mutation–selection balance and the evolutionary advantage of sex and recombination’ by Brian Charlesworth

Published online by Cambridge University Press:  29 October 2008

SARAH P. OTTO*
Affiliation:
Department of Zoology, University of British Columbia, 6270 University Blvd, Vancouver, BC V6T 1Z4, Canada
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Abstract

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Article Commentary
Copyright
Copyright © 2008 Cambridge University Press
Figure 0

Fig. 1. Selection and mutation in Charlesworth's (1990) model. If the number of heterozygous mutant alleles per diploid genome, n, is normally distributed (black curve), then selection acting according to eqn (1) preserves normality. This is because both the normal distribution, f\lpar n \rpar \equals {{\exp \lsqb {\hskip-2pt \minus \lpar {n \minus \bar{n}} \rpar^{\setnum{2}} \sol 2V} \rsqb} \sol {\sqrt {2\pi V}}}, and w(n) are quadratic functions of n in the exponent, and their product f(n)w(n) remains so. Dividing by the mean fitness, the distribution after selection is a normal distribution (long dashed curve) with a new mean, \bar{n}^{\rm s} \equals {{\lpar {\bar{n} \minus V \alpha } \rpar} \sol {\lpar {1 \plus 2 V \beta } \rpar}}, and variance Vs=V/(1+2Vβ). Notice that selection reduces variability whenever there is negative epistasis (β>0). Mutations, on the other hand, are Poisson-distributed, not normally distributed, and so introduce some skew. This skew is relatively minor as long as selection is weak, because the sum of several generations of mutations that are relatively unhindered by selection is approximately normally distributed. Accordingly, the distribution resulting from mutation is approximately normal (short dashed curve) with a new mean, \bar{n}^{\rm m} \equals \bar{n} \plus U, and variance Vm=V+U, where U is the diploid genome-wide deleterious mutation rate.