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A Proof of the Theorem of Pythagoras
Published online by Cambridge University Press: 31 October 2008
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The triangle ABC has a right angle at B. On AC, on the same side as B, describe a square ADEC. Draw DF perpendicular to AB or AB produced.
The triangles ABC and DFA are congruent, having sides CA and AD equal, and the corresponding angles equal. Hence DF is equal to AB.
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- Copyright © Edinburgh Mathematical Society 1930
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