1 Introduction
The study of spectral synthesis started with the fundamental paper of L. Schwartz [Reference Schwartz1], where the following result was proved:
Theorem 1. Every mean periodic function is the sum of a series of exponential monomials which are limits of linear combinations of translates of the function.
Here “limit” is meant as uniform limit on compact sets. A continuous complex-valued function on the reals is called mean periodic if the closure – with respect to uniform convergence on compact sets – of the linear span of its translates is a proper subspace in the space of all continuous complex-valued functions. Calling this closure the variety of the function, the above result says that in the variety of each mean periodic function all exponential monomials span a dense subspace.
 The basic concepts in this result can easily be generalized to more general situations. Given a commutative topological group G we denote by 
 $\mathcal C(G)$
 the space of all continuous complex-valued functions equipped with the topology of uniform convergence on compact sets and with the pointwise addition and pointwise multiplication with scalars. If f is in
$\mathcal C(G)$
 the space of all continuous complex-valued functions equipped with the topology of uniform convergence on compact sets and with the pointwise addition and pointwise multiplication with scalars. If f is in 
 $\mathcal C(G)$
 and y is in G, then
$\mathcal C(G)$
 and y is in G, then 
 $\tau _yf$
 denotes the translate of f defined by
$\tau _yf$
 denotes the translate of f defined by 
 $$ \begin{align*}\tau_yf(x)=f(x+y) \end{align*} $$
$$ \begin{align*}\tau_yf(x)=f(x+y) \end{align*} $$
for each x in g. A closed linear subspace V in 
 $\mathcal C(G)$
 is called a variety on G if it is translation invariant, that is,
$\mathcal C(G)$
 is called a variety on G if it is translation invariant, that is, 
 $\tau _yf$
 is in V for each f in V and y in G. Given an f in
$\tau _yf$
 is in V for each f in V and y in G. Given an f in 
 $\mathcal C(G)$
 the intersection of all varieties including f is denoted by
$\mathcal C(G)$
 the intersection of all varieties including f is denoted by 
 $\tau (f)$
, and it is called the variety of f.
$\tau (f)$
, and it is called the variety of f.
 Given a commutative topological group G continuous complex homomorphisms of G into the multiplicative group of nonzero complex numbers are called exponentials, and continuous complex homomorphisms of G into the additive group of complex numbers are called additive functions. The elements of the function algebra in 
 $\mathcal C(G)$
 generated by all exponentials and additive functions are called exponential polynomials. Functions of the form
$\mathcal C(G)$
 generated by all exponentials and additive functions are called exponential polynomials. Functions of the form 
 $$ \begin{align} f(x)=P\big(a_1(x),a_2(x),\dots,a_k(x)\big)m(x) \end{align} $$
$$ \begin{align} f(x)=P\big(a_1(x),a_2(x),\dots,a_k(x)\big)m(x) \end{align} $$
are called exponential monomials, if 
 $P:\mathbb {C}^k\to \mathbb {C}$
 is a complex polynomial in k variables,
$P:\mathbb {C}^k\to \mathbb {C}$
 is a complex polynomial in k variables, 
 $a_1,a_2,\dots ,a_k$
 are additive functions, and m is an exponential. Every exponential polynomial is a linear combination of exponential monomials. If
$a_1,a_2,\dots ,a_k$
 are additive functions, and m is an exponential. Every exponential polynomial is a linear combination of exponential monomials. If 
 $m=1$
, then the above function is called a polynomial.
$m=1$
, then the above function is called a polynomial.
 Using these concepts we say that the variety V on G is synthesizable, if exponential monomials span a dense subspace in it. We say that spectral synthesis holds on V, if every subvariety of V is synthesizable. We say that spectral synthesis holds on the group G, or the group G is synthesizable, if every variety on G is synthesizable. Hence Schwartz’s theorem can be formulated by saying that spectral synthesis holds on 
 $\mathbb {R}$
. In the paper [Reference Lefranc2], M. Lefranc proved that spectral synthesis holds on
$\mathbb {R}$
. In the paper [Reference Lefranc2], M. Lefranc proved that spectral synthesis holds on 
 $\mathbb {Z}^n$
. In [Reference Elliott4], R. J. Elliott made an attempt to prove that spectral synthesis holds on every discrete Abelian group, but his proof was incorrect. In fact, a counterexample for Elliott’s statement was given in [Reference Székelyhidi7]. In [Reference Laczkovich and Székelyhidi8], a characterization theorem was proved for discrete Abelian groups having spectral synthesis.
$\mathbb {Z}^n$
. In [Reference Elliott4], R. J. Elliott made an attempt to prove that spectral synthesis holds on every discrete Abelian group, but his proof was incorrect. In fact, a counterexample for Elliott’s statement was given in [Reference Székelyhidi7]. In [Reference Laczkovich and Székelyhidi8], a characterization theorem was proved for discrete Abelian groups having spectral synthesis.
In the present paper we give a complete characterization of those locally compact Abelian groups on which spectral synthesis holds. Using the localization method we worked out in [Reference Székelyhidi9], we can show that if a locally compact Abelian group is synthesizable, then so is its extensions by a locally compact Abelian group consisting of compact elements (see [Reference Székelyhidi10]). Also, here we prove that if a locally compact Abelian group is synthesizable, and on its extensions to a direct sum with the group of integers (see [Reference Székelyhidi12]). Finally, using the results of Schwartz [Reference Schwartz1] and Gurevich [Reference Gurevič6] we apply the structure theory of locally compact Abelian groups.
2 Derivations of the Fourier algebra
In this section we recall some concepts and results concerning the Fourier algebra of locally compact Abelian groups.
 Given a locally compact Abelian group G we denote by 
 $\mathcal M_c(G)$
 its measure algebra, which is the space of all compactly supported complex Borel measures on G. This space is identified with the topological dual of
$\mathcal M_c(G)$
 its measure algebra, which is the space of all compactly supported complex Borel measures on G. This space is identified with the topological dual of 
 $\mathcal C(G)$
 equipped with the weak*-topology. In fact,
$\mathcal C(G)$
 equipped with the weak*-topology. In fact, 
 $\mathcal M_c(G)$
 is a topological algebra with the convolution of measures defined by
$\mathcal M_c(G)$
 is a topological algebra with the convolution of measures defined by 
 $$ \begin{align*}\langle \mu*\nu,f\rangle =\int \int f(x+y)\,d\mu(x)\,d\nu(y) \end{align*} $$
$$ \begin{align*}\langle \mu*\nu,f\rangle =\int \int f(x+y)\,d\mu(x)\,d\nu(y) \end{align*} $$
for each 
 $\mu ,\nu $
 in
$\mu ,\nu $
 in 
 $\mathcal M_c(G)$
 and f in
$\mathcal M_c(G)$
 and f in 
 $\mathcal C(G)$
. In addition,
$\mathcal C(G)$
. In addition, 
 $\mathcal C(G)$
 is a topological vector module over
$\mathcal C(G)$
 is a topological vector module over 
 $\mathcal M_c(G)$
. It is clear that varieties on G are exactly the closed submodules of
$\mathcal M_c(G)$
. It is clear that varieties on G are exactly the closed submodules of 
 $\mathcal C(G)$
, and we have a one-to-one correspondence between closed ideals in
$\mathcal C(G)$
, and we have a one-to-one correspondence between closed ideals in 
 $\mathcal M_c(G)$
 and varieties in
$\mathcal M_c(G)$
 and varieties in 
 $\mathcal C(G)$
 established by the annihilators:
$\mathcal C(G)$
 established by the annihilators: 
 $V\leftrightarrow \mathrm {Ann\,} V$
 and
$V\leftrightarrow \mathrm {Ann\,} V$
 and 
 $I\leftrightarrow \mathrm {Ann\,} I$
 for each variety V and closed ideal I. For the sake of simplicity, we say that the closed ideal I in
$I\leftrightarrow \mathrm {Ann\,} I$
 for each variety V and closed ideal I. For the sake of simplicity, we say that the closed ideal I in 
 $\mathcal M_c(G)$
 is synthesizable, if the variety
$\mathcal M_c(G)$
 is synthesizable, if the variety 
 $\mathrm {Ann\,} I$
 is synthesizable.
$\mathrm {Ann\,} I$
 is synthesizable.
 Let G be a locally compact Abelian group and let 
 $\mathcal A(G)$
 denote its Fourier algebra, that is, the algebra of all Fourier transforms of compactly supported complex Borel measures on G. We recall that the Fourier transform defined by
$\mathcal A(G)$
 denote its Fourier algebra, that is, the algebra of all Fourier transforms of compactly supported complex Borel measures on G. We recall that the Fourier transform defined by 
 $$ \begin{align*}\widehat{\mu}(m)=\int m(-x)\,d\mu(x) \end{align*} $$
$$ \begin{align*}\widehat{\mu}(m)=\int m(-x)\,d\mu(x) \end{align*} $$
for each 
 $\mu $
 in the measure algebra is the extension of the Fourier–Laplace transform on the dual group: here m is not necessarily a unitary exponential, that is, a character of G, but it can be any complex exponential on G.
$\mu $
 in the measure algebra is the extension of the Fourier–Laplace transform on the dual group: here m is not necessarily a unitary exponential, that is, a character of G, but it can be any complex exponential on G.
 The algebra 
 $\mathcal A(G)$
 is topologically isomorphic to the measure algebra
$\mathcal A(G)$
 is topologically isomorphic to the measure algebra 
 $\mathcal M_c(G)$
. For the sake of simplicity, if the annihilator
$\mathcal M_c(G)$
. For the sake of simplicity, if the annihilator 
 $\mathrm {Ann\,} I$
 of the closed ideal I in
$\mathrm {Ann\,} I$
 of the closed ideal I in 
 $\mathcal M_c(G)$
 is synthesizable, then we say that the corresponding closed ideal
$\mathcal M_c(G)$
 is synthesizable, then we say that the corresponding closed ideal 
 $\widehat {I}$
 in
$\widehat {I}$
 in 
 $\mathcal A(G)$
 is synthesizable. Given an ideal
$\mathcal A(G)$
 is synthesizable. Given an ideal 
 $\widehat {I}$
 in
$\widehat {I}$
 in 
 $\mathcal A(G)$
 a root of
$\mathcal A(G)$
 a root of 
 $\widehat {I}$
 is an exponential m at which every
$\widehat {I}$
 is an exponential m at which every 
 $\widehat {\mu }$
 vanishes. The set of all roots of the ideal
$\widehat {\mu }$
 vanishes. The set of all roots of the ideal 
 $\widehat {I}$
 is denoted by
$\widehat {I}$
 is denoted by 
 $Z(\widehat {I})$
.
$Z(\widehat {I})$
.
 The continuous linear operator 
 $D:\mathcal A(G)\to \mathcal A(G)$
 is called a derivation of order one, if
$D:\mathcal A(G)\to \mathcal A(G)$
 is called a derivation of order one, if 
 $$ \begin{align*}D(\widehat{\mu}\cdot \widehat{\nu})=D(\widehat{\mu})\cdot \widehat{\nu}+ \widehat{\mu}\cdot D(\widehat{\nu}) \end{align*} $$
$$ \begin{align*}D(\widehat{\mu}\cdot \widehat{\nu})=D(\widehat{\mu})\cdot \widehat{\nu}+ \widehat{\mu}\cdot D(\widehat{\nu}) \end{align*} $$
holds for each 
 $\widehat {\mu }, \widehat {\nu }$
 in
$\widehat {\mu }, \widehat {\nu }$
 in 
 $\mathcal A(G)$
. For each natural number
$\mathcal A(G)$
. For each natural number 
 $n\geq 1$
, the continuous linear operator
$n\geq 1$
, the continuous linear operator 
 $D:\mathcal A(G)\to \mathcal A(G)$
 is called a derivation of order
$D:\mathcal A(G)\to \mathcal A(G)$
 is called a derivation of order 
 $n+1$
, if the bilinear operator
$n+1$
, if the bilinear operator 
 $$ \begin{align*}(\widehat{\mu}, \widehat{\nu})\to D(\widehat{\mu}\cdot \widehat{\nu})-D(\widehat{\mu})\cdot \widehat{\nu}- \widehat{\mu}\cdot D(\widehat{\nu}) \end{align*} $$
$$ \begin{align*}(\widehat{\mu}, \widehat{\nu})\to D(\widehat{\mu}\cdot \widehat{\nu})-D(\widehat{\mu})\cdot \widehat{\nu}- \widehat{\mu}\cdot D(\widehat{\nu}) \end{align*} $$
is a derivation of order n in both variables. All constant multiples of the identity operator on 
 $\mathcal A(G)$
 are considered derivations of order
$\mathcal A(G)$
 are considered derivations of order 
 $0$
. Finally, we call a linear operator on
$0$
. Finally, we call a linear operator on 
 $\mathcal A(G)$
 a derivation, if it is a derivation of order n for some natural number n. It is easy to see that all derivations on
$\mathcal A(G)$
 a derivation, if it is a derivation of order n for some natural number n. It is easy to see that all derivations on 
 $\mathcal A(G)$
 form a commutative algebra with unit (see [Reference Székelyhidi9, Theorem 4]). The elements of the subalgebra generated by derivations of order not greater than
$\mathcal A(G)$
 form a commutative algebra with unit (see [Reference Székelyhidi9, Theorem 4]). The elements of the subalgebra generated by derivations of order not greater than 
 $1$
 are called polynomial derivations – in fact, they are polynomials of derivations of order at most
$1$
 are called polynomial derivations – in fact, they are polynomials of derivations of order at most 
 $1$
.
$1$
.
 Given a continuous linear operator F on 
 $\mathcal A(G)$
 and an exponential m on G the continuous function
$\mathcal A(G)$
 and an exponential m on G the continuous function 
 $f_{F,m}:G\to \mathbb {C}$
 defined for x in G by
$f_{F,m}:G\to \mathbb {C}$
 defined for x in G by 
 $$ \begin{align*}f_{F,m}(x)=F(\widehat{\delta}_x)(m)m(x) \end{align*} $$
$$ \begin{align*}f_{F,m}(x)=F(\widehat{\delta}_x)(m)m(x) \end{align*} $$
is called the generating function of F. The following proposition shows that each continuous linear operator on 
 $\mathcal A(G)$
 is uniquely determined by its generating function.
$\mathcal A(G)$
 is uniquely determined by its generating function.
Proposition 1. Let F be a continuous linear operator on 
 $\mathcal A(G)$
. Then
$\mathcal A(G)$
. Then 

holds for each exponential m and for every 
 $\widehat {\mu }$
 in
$\widehat {\mu }$
 in 
 $\mathcal A(G)$
.
$\mathcal A(G)$
.
Proof. For each exponential m, the mapping 
 $\mu \mapsto F(\widehat {\mu })(m)$
 defines a continuous linear functional on the measure algebra
$\mu \mapsto F(\widehat {\mu })(m)$
 defines a continuous linear functional on the measure algebra 
 $\mathcal M_c(G)$
. We conclude (see e.g. [Reference Rudin5, 3.10 Theorem]) that there exists a continuous function
$\mathcal M_c(G)$
. We conclude (see e.g. [Reference Rudin5, 3.10 Theorem]) that there exists a continuous function 
 $\varphi _m:G\to \mathbb {C}$
 such that
$\varphi _m:G\to \mathbb {C}$
 such that 
 $$ \begin{align*} F(\widehat{\mu})(m)=\int \varphi_m(z)\,d\mu(z) \end{align*} $$
$$ \begin{align*} F(\widehat{\mu})(m)=\int \varphi_m(z)\,d\mu(z) \end{align*} $$
holds for each 
 $\mu $
 in
$\mu $
 in 
 $\mathcal M_c(G)$
. Then we have
$\mathcal M_c(G)$
. Then we have 
 $$ \begin{align*} \varphi_m(x)=\int \varphi_m(z)\,d\delta_x(z)=F(\widehat{\delta}_x)(m), \end{align*} $$
$$ \begin{align*} \varphi_m(x)=\int \varphi_m(z)\,d\delta_x(z)=F(\widehat{\delta}_x)(m), \end{align*} $$
hence  , which yields (2).
, which yields (2).
Clearly, the generating function of the identity operator is the identically one function, and it is easy to check that the generating function of a first order derivation is an additive function, and conversely, each additive function generates a first order derivation. It follows that the generating function of a polynomial derivation is a polynomial, and the degree of the generating polynomial is equal to the order of the corresponding polynomial derivation (see also [Reference Székelyhidi9]).
 In general, there may exist nonpolynomial derivations on the Fourier algebra. However, the generating function 
 $\varphi $
 of any derivation is a so-called generalized polynomial, which, by definition, satisfies the higher order difference equation
$\varphi $
 of any derivation is a so-called generalized polynomial, which, by definition, satisfies the higher order difference equation 
 $$ \begin{align} \Delta_{y_1,y_2,\dots,y_{n+1}}\varphi(x)=0. \end{align} $$
$$ \begin{align} \Delta_{y_1,y_2,\dots,y_{n+1}}\varphi(x)=0. \end{align} $$
Here 
 $\Delta _y=\tau _y-\tau _0$
, and
$\Delta _y=\tau _y-\tau _0$
, and 
 $\Delta _{y_1,y_2,\dots ,y_{n+1}}$
 is the product of the linear operators
$\Delta _{y_1,y_2,\dots ,y_{n+1}}$
 is the product of the linear operators 
 $\tau _{y_i}-\tau _0$
 for
$\tau _{y_i}-\tau _0$
 for 
 $i=1,2,\dots ,n+1$
 (see [Reference Székelyhidi9]). Polynomials are generalized polynomials, but the converse is not true. Still all generalized polynomials generate derivations, which are not polynomial derivations. We shall see that the existence of nonpolynomial derivations is closely related to the failure of spectral synthesis.
$i=1,2,\dots ,n+1$
 (see [Reference Székelyhidi9]). Polynomials are generalized polynomials, but the converse is not true. Still all generalized polynomials generate derivations, which are not polynomial derivations. We shall see that the existence of nonpolynomial derivations is closely related to the failure of spectral synthesis.
 Given a derivation D and an exponential m we denote by 
 $\widehat {I}_{D,m}$
 the set of all functions
$\widehat {I}_{D,m}$
 the set of all functions 
 $\widehat {\mu }$
 in
$\widehat {\mu }$
 in 
 $\mathcal A(G)$
 which are annihilated at m by all derivations of the form
$\mathcal A(G)$
 which are annihilated at m by all derivations of the form 

where 
 $\varphi $
 belongs to the translation invariant linear space in
$\varphi $
 belongs to the translation invariant linear space in 
 $\mathcal C(G)$
 generated by
$\mathcal C(G)$
 generated by 
 $f_{D,m}$
. In other words,
$f_{D,m}$
. In other words, 
 $\widehat {I}_{D,m}$
 is the set of those functions
$\widehat {I}_{D,m}$
 is the set of those functions 
 $\widehat {\mu }$
 in
$\widehat {\mu }$
 in 
 $\mathcal A(G)$
 which satisfy
$\mathcal A(G)$
 which satisfy 
 $\widehat {\mu }(m)=D\widehat {\mu }(m)=0$
, and
$\widehat {\mu }(m)=D\widehat {\mu }(m)=0$
, and 

for each positive integer k and 
 $y_1,y_2,\dots ,y_k$
 in G. It is easy to see that for every derivation D on
$y_1,y_2,\dots ,y_k$
 in G. It is easy to see that for every derivation D on 
 $\mathcal A(G)$
 and for each exponential m, we have the equation
$\mathcal A(G)$
 and for each exponential m, we have the equation  (see [Reference Székelyhidi9]). As a by-product we obtain that
 (see [Reference Székelyhidi9]). As a by-product we obtain that 
 $I_{D,m}$
, as well as
$I_{D,m}$
, as well as 
 $\widehat {I}_{D,m}$
 is a closed ideal, hence so is the intersection
$\widehat {I}_{D,m}$
 is a closed ideal, hence so is the intersection 
 $\widehat {I}_{\mathcal {D},m}=\bigcap _{D\in \mathcal D} \widehat {I}_{D,m}$
 for any family
$\widehat {I}_{\mathcal {D},m}=\bigcap _{D\in \mathcal D} \widehat {I}_{D,m}$
 for any family 
 $\mathcal D$
 of derivations.
$\mathcal D$
 of derivations.
 We note that for a polynomial derivation 
 $P(D_1,D_2,\dots ,D_k)$
 the set
$P(D_1,D_2,\dots ,D_k)$
 the set 
 $\widehat {I}_{D,m}$
 consists of those Fourier transforms
$\widehat {I}_{D,m}$
 consists of those Fourier transforms 
 $\widehat {\mu }$
 in
$\widehat {\mu }$
 in 
 $\mathcal A(G)$
 that satisfy
$\mathcal A(G)$
 that satisfy 
 $$ \begin{align*}(\partial^{\alpha_1}\partial^{\alpha_2}\cdots \partial^{\alpha_k}P)(D_1,D_2,\dots,D_k)(\widehat{\mu})(m)=0 \end{align*} $$
$$ \begin{align*}(\partial^{\alpha_1}\partial^{\alpha_2}\cdots \partial^{\alpha_k}P)(D_1,D_2,\dots,D_k)(\widehat{\mu})(m)=0 \end{align*} $$
for every choice of the nonnegative integers 
 $\alpha _i$
.
$\alpha _i$
.
 The dual concept is the following: given a closed ideal 
 $\widehat {I}$
 in
$\widehat {I}$
 in 
 $\mathcal A(G)$
 and an exponential m, the set of all derivations annihilating
$\mathcal A(G)$
 and an exponential m, the set of all derivations annihilating 
 $\widehat {I}$
 at m is denoted by
$\widehat {I}$
 at m is denoted by 
 $\mathcal {D}_{\widehat {I},m}$
. The subset of
$\mathcal {D}_{\widehat {I},m}$
. The subset of 
 $\mathcal {D}_{\widehat {I},m}$
 consisting of all polynomial derivations is denoted by
$\mathcal {D}_{\widehat {I},m}$
 consisting of all polynomial derivations is denoted by 
 $\mathcal {P}_{\widehat {I},m}$
. Clearly, we have the inclusion
$\mathcal {P}_{\widehat {I},m}$
. Clearly, we have the inclusion 
 $$ \begin{align} \widehat{I}\subseteq \bigcap_m \widehat{I}_{\mathcal{D}_{\widehat{I},m},m}\subseteq \bigcap_m \widehat{I}_{\mathcal{P}_{\widehat{I},m},m}. \end{align} $$
$$ \begin{align} \widehat{I}\subseteq \bigcap_m \widehat{I}_{\mathcal{D}_{\widehat{I},m},m}\subseteq \bigcap_m \widehat{I}_{\mathcal{P}_{\widehat{I},m},m}. \end{align} $$
We note that if m is not a root of 
 $\widehat {I}$
, then
$\widehat {I}$
, then 
 $\mathcal {D}_{\widehat {I},m}=\mathcal {P}_{\widehat {I},m}=\{0\}$
, consequently
$\mathcal {D}_{\widehat {I},m}=\mathcal {P}_{\widehat {I},m}=\{0\}$
, consequently 
 $\widehat {I}_{\mathcal {D}_{\widehat {I},m},m}=\widehat {I}_{\mathcal {P}_{\widehat {I},m},m}=\mathcal A(G)$
, hence those terms have no effect on the intersection.
$\widehat {I}_{\mathcal {D}_{\widehat {I},m},m}=\widehat {I}_{\mathcal {P}_{\widehat {I},m},m}=\mathcal A(G)$
, hence those terms have no effect on the intersection.
Proposition 2. Let 
 $\mathcal D$
 be a family of derivations on
$\mathcal D$
 be a family of derivations on 
 $\mathcal A(G)$
. The ideal
$\mathcal A(G)$
. The ideal 
 $\widehat {I}$
 in
$\widehat {I}$
 in 
 $\mathcal A(G)$
 has the property
$\mathcal A(G)$
 has the property 
 $$ \begin{align} \widehat{I}\supseteq \bigcap_m \widehat{I}_{\mathcal D,m} \end{align} $$
$$ \begin{align} \widehat{I}\supseteq \bigcap_m \widehat{I}_{\mathcal D,m} \end{align} $$
if and only if the functions  with D in
 with D in 
 $\mathcal D$
 span a dense subspace in
$\mathcal D$
 span a dense subspace in 
 $\mathrm {Ann\,} I$
.
$\mathrm {Ann\,} I$
.
Proof. Let 
 $\widehat {J}=\bigcap _m \widehat {I}_{\mathcal D,m}$
, and assume that
$\widehat {J}=\bigcap _m \widehat {I}_{\mathcal D,m}$
, and assume that 
 $\widehat {J}\subseteq \widehat {I}$
. If the subspace spanned by all functions of the form
$\widehat {J}\subseteq \widehat {I}$
. If the subspace spanned by all functions of the form  with D in
 with D in 
 $\mathcal D$
 is not dense in
$\mathcal D$
 is not dense in 
 $\mathrm {Ann\,} I$
, then there exists a
$\mathrm {Ann\,} I$
, then there exists a 
 $\mu _0$
 not in
$\mu _0$
 not in 
 $\mathrm {Ann\,} \mathrm {Ann\,} I=I$
 such that
$\mathrm {Ann\,} \mathrm {Ann\,} I=I$
 such that 
 $\mu _0$
 annihilates all functions of the form
$\mu _0$
 annihilates all functions of the form  with D in
 with D in 
 $\mathcal D$
. In other words, for each x in G we have
$\mathcal D$
. In other words, for each x in G we have 

In particular, for 
 $x=0$
$x=0$
 

holds for each D in 
 $\mathcal D$
 and for every m. Consequently,
$\mathcal D$
 and for every m. Consequently, 
 $\widehat {\mu }_0$
 is in
$\widehat {\mu }_0$
 is in 
 $\widehat {I}_{\mathcal {D},m}$
 for each m, hence it is in the set
$\widehat {I}_{\mathcal {D},m}$
 for each m, hence it is in the set 
 $\widehat {J}$
, but not in
$\widehat {J}$
, but not in 
 $\widehat {I}$
 – a contradiction.
$\widehat {I}$
 – a contradiction.
 Conversely, assume that the subspace spanned by all functions of the form  with D in
 with D in 
 $\mathcal D$
, is dense in
$\mathcal D$
, is dense in 
 $\mathrm {Ann\,} I$
. It follows that any
$\mathrm {Ann\,} I$
. It follows that any 
 $\mu $
 in
$\mu $
 in 
 $\mathcal M_c(G)$
, which satisfies
$\mathcal M_c(G)$
, which satisfies 

for all D in 
 $\mathcal D$
 and x in G, belongs to
$\mathcal D$
 and x in G, belongs to 
 $I=\mathrm {Ann\,} \mathrm {Ann\,} I$
. Now let
$I=\mathrm {Ann\,} \mathrm {Ann\,} I$
. Now let 
 $\widehat {\mu }$
 be in
$\widehat {\mu }$
 be in 
 $\widehat {I}_{\mathcal D,m}$
 for some m, and suppose that D is in
$\widehat {I}_{\mathcal D,m}$
 for some m, and suppose that D is in 
 $\mathcal D$
. Then for each x in G, the function
$\mathcal D$
. Then for each x in G, the function 
 $\widehat {\mu }\cdot \widehat {\delta }_{-x}$
 is in
$\widehat {\mu }\cdot \widehat {\delta }_{-x}$
 is in 
 $\widehat {I}_{\mathcal D,m}$
, hence
$\widehat {I}_{\mathcal D,m}$
, hence 

that is, 
 $\widehat {\mu }$
 satisfies (6) for each D in
$\widehat {\mu }$
 satisfies (6) for each D in 
 $\mathcal D$
. This implies that
$\mathcal D$
. This implies that 
 $\mu $
 is in I, and the theorem is proved.
$\mu $
 is in I, and the theorem is proved.
Corollary 1. Let 
 $\widehat {I}$
 be a closed ideal in
$\widehat {I}$
 be a closed ideal in 
 $\mathcal A(G)$
. Then
$\mathcal A(G)$
. Then 
 $\widehat {I}=\bigcap _{m\in Z(\widehat {I})} \widehat {I}_{\mathcal P_{\widehat {I},m},m}$
 holds if and only if all functions of the form
$\widehat {I}=\bigcap _{m\in Z(\widehat {I})} \widehat {I}_{\mathcal P_{\widehat {I},m},m}$
 holds if and only if all functions of the form  with m in
 with m in 
 $Z(\widehat {I})$
 and D in
$Z(\widehat {I})$
 and D in 
 $\mathcal P_{\widehat {I},m}$
 span a dense subspace in the variety
$\mathcal P_{\widehat {I},m}$
 span a dense subspace in the variety 
 $\mathrm {Ann\,} I$
.
$\mathrm {Ann\,} I$
.
3 Localization
 The ideal 
 $\widehat {I}$
 is called localizable, if we have equalities in (4). Roughly speaking, localizability of an ideal means that the ideal is completely determined by the values of “derivatives” of the functions belonging to this ideal. Nonlocalizability of the ideal
$\widehat {I}$
 is called localizable, if we have equalities in (4). Roughly speaking, localizability of an ideal means that the ideal is completely determined by the values of “derivatives” of the functions belonging to this ideal. Nonlocalizability of the ideal 
 $\widehat {I}$
 means that there is a
$\widehat {I}$
 means that there is a 
 $\widehat {\nu }$
 not in
$\widehat {\nu }$
 not in 
 $\widehat {I}$
, which is annihilated by all polynomial derivations which annihilate
$\widehat {I}$
, which is annihilated by all polynomial derivations which annihilate 
 $\widehat {I}$
 at its zeros.
$\widehat {I}$
 at its zeros.
Theorem 2. Let G be a locally compact Abelian group. The ideal 
 $\widehat {I}$
 in
$\widehat {I}$
 in 
 $\mathcal A(G)$
 is localizable if and only if it is synthesizable.
$\mathcal A(G)$
 is localizable if and only if it is synthesizable.
Proof. Assume that 
 $\mathrm {Ann\,} I$
 is not synthesizable. Then the linear span of the exponential monomials in
$\mathrm {Ann\,} I$
 is not synthesizable. Then the linear span of the exponential monomials in 
 $\mathrm {Ann\,} I$
 is not dense. In other words, there is a
$\mathrm {Ann\,} I$
 is not dense. In other words, there is a 
 $\widehat {\nu }$
 not in
$\widehat {\nu }$
 not in 
 $\widehat {I}$
 such that
$\widehat {I}$
 such that 
 $\nu *pm=0$
 for every polynomial p such that
$\nu *pm=0$
 for every polynomial p such that 
 $pm$
 is in
$pm$
 is in 
 $\mathrm {Ann\,} I$
. For each such
$\mathrm {Ann\,} I$
. For each such 
 $pm$
 we consider the polynomial derivation
$pm$
 we consider the polynomial derivation 

whenever 
 $\widehat {\mu }$
 is in
$\widehat {\mu }$
 is in 
 $\mathcal A(G)$
. As
$\mathcal A(G)$
. As 
 $pm$
 is in
$pm$
 is in 
 $\mathrm {Ann\,} I$
, hence D is in
$\mathrm {Ann\,} I$
, hence D is in 
 $\mathcal P_{\widehat {I},m}$
. On the other hand, every derivation in
$\mathcal P_{\widehat {I},m}$
. On the other hand, every derivation in 
 $\mathcal P_{\widehat {I},m}$
 has this form with some
$\mathcal P_{\widehat {I},m}$
 has this form with some 
 $pm$
 in
$pm$
 in 
 $\mathrm {Ann\,} I$
. As
$\mathrm {Ann\,} I$
. As 
 $\nu *pm(0)=0$
 for all these functions, we have
$\nu *pm(0)=0$
 for all these functions, we have 

holds for each D in 
 $\mathcal P_{\widehat {I},m}$
. This means that
$\mathcal P_{\widehat {I},m}$
. This means that 
 $\widehat {\nu }$
 is annihilated by all derivations in
$\widehat {\nu }$
 is annihilated by all derivations in 
 $\mathcal P_{\widehat {I},m}$
, but
$\mathcal P_{\widehat {I},m}$
, but 
 $\widehat {\nu }$
 is not in
$\widehat {\nu }$
 is not in 
 $\widehat {I}$
, which contradicts the localizability.
$\widehat {I}$
, which contradicts the localizability.
 Now we assume that 
 $\mathrm {Ann\,} I$
 is synthesizable. This means that all functions of the form
$\mathrm {Ann\,} I$
 is synthesizable. This means that all functions of the form  with m in
 with m in 
 $Z(\widehat {I})$
 and D in
$Z(\widehat {I})$
 and D in 
 $\mathcal P_{\widehat {I},m}$
 span a dense subspace in the variety
$\mathcal P_{\widehat {I},m}$
 span a dense subspace in the variety 
 $\mathrm {Ann\,} I$
. By Corollary 1,
$\mathrm {Ann\,} I$
. By Corollary 1, 
 $$ \begin{align*} \widehat{I}=\bigcap_{m\in Z(\widehat{I})} \widehat{I}_{\mathcal P_{\widehat{I},m},m}. \end{align*} $$
$$ \begin{align*} \widehat{I}=\bigcap_{m\in Z(\widehat{I})} \widehat{I}_{\mathcal P_{\widehat{I},m},m}. \end{align*} $$
We show that this ideal is localizable. Assuming the contrary, there is an exponential m in 
 $Z(\widehat {I})$
 and there is a
$Z(\widehat {I})$
 and there is a 
 $\widehat {\nu }$
 not in
$\widehat {\nu }$
 not in 
 $\widehat {I}_{\mathcal P_{\widehat {I},m},m}$
 such that
$\widehat {I}_{\mathcal P_{\widehat {I},m},m}$
 such that 
 $D(\widehat {\nu })(m)=0$
 for each derivation D in
$D(\widehat {\nu })(m)=0$
 for each derivation D in 
 $\mathcal P_{\widehat {I},m}$
. In other words,
$\mathcal P_{\widehat {I},m}$
. In other words, 
 $\widehat {\nu }$
 is annihilated at m by all derivations in
$\widehat {\nu }$
 is annihilated at m by all derivations in 
 $\mathcal P_{\widehat {I},m}$
, and still
$\mathcal P_{\widehat {I},m}$
, and still 
 $\widehat {\nu }$
 is not in
$\widehat {\nu }$
 is not in 
 $\widehat {I}_{\mathcal P_{\widehat {I},m},m}$
 – a contradiction.
$\widehat {I}_{\mathcal P_{\widehat {I},m},m}$
 – a contradiction.
4 Compact elements
In this section we show that if spectral synthesis holds on a locally compact Abelian group, then it also holds on every extension by a locally compact Abelian group consisting of compact elements.
Theorem 3. Let G be a locally compact Abelian group and let B denote the closed subgroup of G consisting of all compact elements. Then spectral synthesis holds on G if and only if it holds on 
 $G/B$
.
$G/B$
.
Proof. If spectral synthesis holds on G, then it obviously holds on every continuous homomorphic image of G (see [Reference Székelyhidi11, Theorem 3.1]), in particular, it holds on 
 $G/B$
.
$G/B$
.
 Conversely, we assume that spectral synthesis holds on 
 $G/B$
. This means that every closed ideal in the Fourier algebra of
$G/B$
. This means that every closed ideal in the Fourier algebra of 
 $G/B$
 is localizable, and we need to show the same for all closed ideals of the Fourier algebra of G.
$G/B$
 is localizable, and we need to show the same for all closed ideals of the Fourier algebra of G.
 First we remark that the polynomial rings over G and over 
 $G/B$
 can be identified. Indeed, polynomials on G are built up from additive functions on G, which clearly vanish on compact elements, as the additive topological group of complex numbers has no nontrivial compact subgroups. Consequently, if a is an additive function and
$G/B$
 can be identified. Indeed, polynomials on G are built up from additive functions on G, which clearly vanish on compact elements, as the additive topological group of complex numbers has no nontrivial compact subgroups. Consequently, if a is an additive function and 
 $x,y$
 are in the same coset of B, then
$x,y$
 are in the same coset of B, then 
 $x-y$
 is in B, and
$x-y$
 is in B, and 
 $a(x-y)=0$
, which means
$a(x-y)=0$
, which means 
 $a(x)=a(y)$
. So, the additive functions on G arise from the additive functions of
$a(x)=a(y)$
. So, the additive functions on G arise from the additive functions of 
 $G/B$
, hence the two polynomial rings can be identified.
$G/B$
, hence the two polynomial rings can be identified.
 Now we define a projection of the Fourier algebra of G into the Fourier algebra of 
 $G/B$
 as follows. Let
$G/B$
 as follows. Let 
 $\Phi :G\to G/B$
 denote the natural mapping. For each measure
$\Phi :G\to G/B$
 denote the natural mapping. For each measure 
 $\mu $
 in
$\mu $
 in 
 $\mathcal M_c(G)$
 we define
$\mathcal M_c(G)$
 we define 
 $\mu _B$
 as the linear functional
$\mu _B$
 as the linear functional 
 $$ \begin{align*} \langle \mu_B,\varphi\rangle=\langle \mu, \varphi\circ \Phi\rangle \end{align*} $$
$$ \begin{align*} \langle \mu_B,\varphi\rangle=\langle \mu, \varphi\circ \Phi\rangle \end{align*} $$
whenever 
 $\varphi :G/B\to \mathbb {C}$
 is a continuous function. It is straightforward that the mapping
$\varphi :G/B\to \mathbb {C}$
 is a continuous function. It is straightforward that the mapping 
 $\widehat {\mu }\mapsto \widehat {\mu }_B$
 is a continuous algebra homomorphism of the Fourier algebra of G into the Fourier algebra of
$\widehat {\mu }\mapsto \widehat {\mu }_B$
 is a continuous algebra homomorphism of the Fourier algebra of G into the Fourier algebra of 
 $G/B$
. As
$G/B$
. As 
 $\Phi $
 is an open mapping, closed ideals are mapped onto closed ideals.
$\Phi $
 is an open mapping, closed ideals are mapped onto closed ideals.
 For a given closed ideal 
 $\widehat {I}$
 in
$\widehat {I}$
 in 
 $\mathcal A(G)$
, we denote by
$\mathcal A(G)$
, we denote by 
 $\widehat {I}_B$
 the closed ideal in
$\widehat {I}_B$
 the closed ideal in 
 $\mathcal A(G/B)$
 which corresponds to
$\mathcal A(G/B)$
 which corresponds to 
 $\widehat {I}$
 under the above homomorphism. If m is a root of the ideal
$\widehat {I}$
 under the above homomorphism. If m is a root of the ideal 
 $\widehat {I}_B$
, then
$\widehat {I}_B$
, then 
 $\widehat {\mu }_B(m)=0$
 for each
$\widehat {\mu }_B(m)=0$
 for each 
 $\widehat {\mu }$
 in
$\widehat {\mu }$
 in 
 $\widehat {I}$
. In other words,
$\widehat {I}$
. In other words, 

hence 
 $m\circ \Phi $
, which is clearly an exponential on G, is a root of
$m\circ \Phi $
, which is clearly an exponential on G, is a root of 
 $\widehat {I}$
. Suppose that D is a derivation in
$\widehat {I}$
. Suppose that D is a derivation in 
 $\mathcal P_{\widehat {I},m\circ \Phi }$
, then it has the form
$\mathcal P_{\widehat {I},m\circ \Phi }$
, then it has the form 

with some polynomial p on G. According to our remark above, the polynomial p can uniquely be written as 
 $p_B\circ \Phi $
, where
$p_B\circ \Phi $
, where 
 $p_B$
 is a polynomial on
$p_B$
 is a polynomial on 
 $G/B$
. In other words,
$G/B$
. In other words, 

which defines a derivation 
 $D_B$
 on
$D_B$
 on 
 $\mathcal A(G/B)$
 with generating function
$\mathcal A(G/B)$
 with generating function 
 $f_{D_B,m}=p_B$
.
$f_{D_B,m}=p_B$
.
 It follows that every derivation in 
 $\mathcal P_{\widehat {I},m\circ \Phi }$
 arises from a derivation in
$\mathcal P_{\widehat {I},m\circ \Phi }$
 arises from a derivation in 
 $\mathcal P_{\widehat {I}_B,m}$
. On the other hand, if d is a derivation in
$\mathcal P_{\widehat {I}_B,m}$
. On the other hand, if d is a derivation in 
 $\mathcal P_{\widehat {I}_B,m}$
, then we have
$\mathcal P_{\widehat {I}_B,m}$
, then we have 

which defines a derivation D in 
 $\mathcal P_{\widehat {I},m\circ \Phi }$
.
$\mathcal P_{\widehat {I},m\circ \Phi }$
.
 We summarize our assertions. Let 
 $\widehat {I}$
 be a proper closed ideal in
$\widehat {I}$
 be a proper closed ideal in 
 $\mathcal A(G)$
 and assume that
$\mathcal A(G)$
 and assume that 
 $\widehat {I}$
 is nonlocalizable. It follows that there is a function
$\widehat {I}$
 is nonlocalizable. It follows that there is a function 
 $\widehat {\nu }$
 not in
$\widehat {\nu }$
 not in 
 $\widehat {I}$
 which is annihilated at M by all polynomial derivations in
$\widehat {I}$
 which is annihilated at M by all polynomial derivations in 
 $\mathcal P_{\widehat {I},M}$
, for each exponential M on G. In particular,
$\mathcal P_{\widehat {I},M}$
, for each exponential M on G. In particular, 
 $\widehat {\nu }$
 is annihilated at
$\widehat {\nu }$
 is annihilated at 
 $m\circ \Phi $
 by all polynomial derivations in
$m\circ \Phi $
 by all polynomial derivations in 
 $\mathcal P_{\widehat {I},m\circ \Phi }$
, for each exponential m on
$\mathcal P_{\widehat {I},m\circ \Phi }$
, for each exponential m on 
 $G/B$
. We have seen above that this implies that
$G/B$
. We have seen above that this implies that 
 $\widehat {\nu }_B$
 is annihilated at m by all polynomial derivations in
$\widehat {\nu }_B$
 is annihilated at m by all polynomial derivations in 
 $\mathcal P_{\widehat {I}_B,m}$
 and for each exponential m on
$\mathcal P_{\widehat {I}_B,m}$
 and for each exponential m on 
 $G/B$
. As spectral synthesis holds on
$G/B$
. As spectral synthesis holds on 
 $G/B$
, the ideal
$G/B$
, the ideal 
 $\widehat {I}_B$
 is localizable, hence
$\widehat {I}_B$
 is localizable, hence 
 $\widehat {\nu }_B$
 is in
$\widehat {\nu }_B$
 is in 
 $\widehat {I}_B$
, but this contradicts the assumption that
$\widehat {I}_B$
, but this contradicts the assumption that 
 $\widehat {\nu }$
 is not in
$\widehat {\nu }$
 is not in 
 $\widehat {I}$
. The proof is complete.
$\widehat {I}$
. The proof is complete.
From this result it follows immediately that if every element of a locally compact Abelian group is compact, then spectral synthesis holds on this group. In particular, spectral synthesis holds on every compact Abelian group. Also, we can provide the following simple proof for the characterization theorem of discrete synthesizable Abelian groups (see [8]):
Corollary 2. Spectral synthesis holds on a discrete Abelian group if and only if its torsion free rank is finite.
Proof. If the torsion free rank of G is infinite, then there is a generalized polynomial on G, which is not a polynomial (see [Reference Székelyhidi7]), hence there is a nonpolynomial derivation on the Fourier algebra. Consequently, we have the chain of inclusions
 $$ \begin{align*} \widehat{I}\subseteq \widehat{I}_{\mathcal D_{{\widehat{I},m}},m}\subsetneq \widehat{I}_{\mathcal P_{{\widehat{I},m}},m}, \end{align*} $$
$$ \begin{align*} \widehat{I}\subseteq \widehat{I}_{\mathcal D_{{\widehat{I},m}},m}\subsetneq \widehat{I}_{\mathcal P_{{\widehat{I},m}},m}, \end{align*} $$
which implies that 
 $\widehat {I}\ne \widehat {I}_{\mathcal P_{{\widehat {I},m}},m}$
, hence
$\widehat {I}\ne \widehat {I}_{\mathcal P_{{\widehat {I},m}},m}$
, hence 
 $\widehat {I}$
 is not synthesizable.
$\widehat {I}$
 is not synthesizable.
 Conversely, let G have finite torsion free rank. The subgroup B of compact elements coincides with the set T of all elements of finite order, and 
 $G/T$
 is a (continuous) homomorphic image of
$G/T$
 is a (continuous) homomorphic image of 
 $\mathbb {Z}^n$
 with some nonnegative integer n. As spectral synthesis holds on
$\mathbb {Z}^n$
 with some nonnegative integer n. As spectral synthesis holds on 
 $\mathbb {Z}^n$
 (see [Reference Lefranc2]), it holds on its homomorphic images.
$\mathbb {Z}^n$
 (see [Reference Lefranc2]), it holds on its homomorphic images.
5 Extension by the integers
 In this section we show that if spectral synthesis holds on a locally compact Abelian group, then it also holds on the group obtained by adding 
 $\mathbb {Z}$
 to it as a direct summand.
$\mathbb {Z}$
 to it as a direct summand.
 It is known that every exponential 
 $e:\mathbb {Z}\to \mathbb {C}$
 has the form
$e:\mathbb {Z}\to \mathbb {C}$
 has the form 
 $$ \begin{align*}e(k)=\lambda^k \end{align*} $$
$$ \begin{align*}e(k)=\lambda^k \end{align*} $$
for k in 
 $\mathbb {Z}$
, where
$\mathbb {Z}$
, where 
 $\lambda $
 is a nonzero complex number, which is uniquely determined by e. For this exponential we use the notation
$\lambda $
 is a nonzero complex number, which is uniquely determined by e. For this exponential we use the notation 
 $e_{\lambda }$
. It follows that for every commutative topological group G, the exponentials on
$e_{\lambda }$
. It follows that for every commutative topological group G, the exponentials on 
 $G\times \mathbb {Z}$
 have the form
$G\times \mathbb {Z}$
 have the form 
 $m\otimes e_{\lambda }:(g,k)\mapsto m(g)e_{\lambda }(k)$
, where m is an exponential on G, and
$m\otimes e_{\lambda }:(g,k)\mapsto m(g)e_{\lambda }(k)$
, where m is an exponential on G, and 
 $\lambda $
 is a nonzero complex number. Hence the Fourier–Laplace transforms in
$\lambda $
 is a nonzero complex number. Hence the Fourier–Laplace transforms in 
 $\mathcal A(G\times \mathbb {Z})$
 can be thought as two variable functions defined on the pairs
$\mathcal A(G\times \mathbb {Z})$
 can be thought as two variable functions defined on the pairs 
 $(m,\lambda )$
, where m is an exponential on G, and
$(m,\lambda )$
, where m is an exponential on G, and 
 $\lambda $
 is a nonzero complex number.
$\lambda $
 is a nonzero complex number.
 Let G be a locally compact Abelian group. For each measure 
 $\mu $
 in
$\mu $
 in 
 $\mathcal M_c(G\times \mathbb {Z})$
 and for every k in
$\mathcal M_c(G\times \mathbb {Z})$
 and for every k in 
 $\mathbb {Z}$
 we let
$\mathbb {Z}$
 we let 
 $$ \begin{align*}S_k(\mu)=\{g:\, g\in G\quad\text{and}\quad (g,k)\in \mathrm{supp\,} \mu\}. \end{align*} $$
$$ \begin{align*}S_k(\mu)=\{g:\, g\in G\quad\text{and}\quad (g,k)\in \mathrm{supp\,} \mu\}. \end{align*} $$
As 
 $\mu $
 is compactly supported, there are only finitely many k’s in
$\mu $
 is compactly supported, there are only finitely many k’s in 
 $\mathbb {Z}$
 such that
$\mathbb {Z}$
 such that 
 $S_k(\mu )$
 is nonempty. We have
$S_k(\mu )$
 is nonempty. We have 
 $$ \begin{align*}\mathrm{supp\,} \mu=\bigcup_{k\in \mathbb{Z}} (S_k(\mu)\times \{k\}), \end{align*} $$
$$ \begin{align*}\mathrm{supp\,} \mu=\bigcup_{k\in \mathbb{Z}} (S_k(\mu)\times \{k\}), \end{align*} $$
and
 $$ \begin{align*}S_k(\mu)\times \{k\}=(G\times \{k\})\cap \mathrm{supp\,} \mu. \end{align*} $$
$$ \begin{align*}S_k(\mu)\times \{k\}=(G\times \{k\})\cap \mathrm{supp\,} \mu. \end{align*} $$
It follows that the sets 
 $S_k(\mu )\times \{k\}$
 are pairwise disjoint compact sets in
$S_k(\mu )\times \{k\}$
 are pairwise disjoint compact sets in 
 $G\times \mathbb {Z}$
, and they are nonempty for finitely many k’s only. The restriction of
$G\times \mathbb {Z}$
, and they are nonempty for finitely many k’s only. The restriction of 
 $\mu $
 to
$\mu $
 to 
 $S_k(\mu )\times \{k\}$
 is denoted by
$S_k(\mu )\times \{k\}$
 is denoted by 
 $\mu _{k}$
. Then, by definition
$\mu _{k}$
. Then, by definition 
 $$ \begin{align*}\langle \mu_k, f\rangle=\int f\cdot \chi_k\,d\mu \end{align*} $$
$$ \begin{align*}\langle \mu_k, f\rangle=\int f\cdot \chi_k\,d\mu \end{align*} $$
for each f in 
 $\mathcal C(G\times \mathbb {Z})$
, where
$\mathcal C(G\times \mathbb {Z})$
, where 
 $\chi _k$
 denotes the characteristic function of the set
$\chi _k$
 denotes the characteristic function of the set 
 $S_k(\mu )\times \{k\}$
. In other words,
$S_k(\mu )\times \{k\}$
. In other words, 
 $$ \begin{align*}\int f\,d\mu_k=\int f(g,k)\,d\mu(g,l) \end{align*} $$
$$ \begin{align*}\int f\,d\mu_k=\int f(g,k)\,d\mu(g,l) \end{align*} $$
holds for each k in 
 $\mathbb {Z}$
 and for every f in
$\mathbb {Z}$
 and for every f in 
 $\mathcal C(G\times \mathbb {Z})$
. Clearly,
$\mathcal C(G\times \mathbb {Z})$
. Clearly, 
 $\mu = \sum _{k\in \mathbb {Z}} \mu _k$
, and this sum is finite.
$\mu = \sum _{k\in \mathbb {Z}} \mu _k$
, and this sum is finite.
Lemma 1. Let 
 $\mu $
 be in
$\mu $
 be in 
 $\mathcal M_c(G\times \mathbb {Z})$
. Then, for each k in
$\mathcal M_c(G\times \mathbb {Z})$
. Then, for each k in 
 $\mathbb {Z}$
, we have
$\mathbb {Z}$
, we have 
 $$ \begin{align*} \mu_k=\mu_0*\delta_{(0,k)}. \end{align*} $$
$$ \begin{align*} \mu_k=\mu_0*\delta_{(0,k)}. \end{align*} $$
 Here 
 $\delta _{(0,k)}$
 denotes the Dirac measure at the point
$\delta _{(0,k)}$
 denotes the Dirac measure at the point 
 $(0,k)$
 in
$(0,k)$
 in 
 $G\times \mathbb {Z}$
.
$G\times \mathbb {Z}$
.
Proof. We have for each f in 
 $\mathcal C(G\times \mathbb {Z})$
:
$\mathcal C(G\times \mathbb {Z})$
: 
 $$ \begin{align*} \langle \mu_0*\delta_{(0,k)},f\rangle&= \int \int f(g+h,l+n)\,d\mu_0(g,l)\,d\delta_{(0,k)}(h,n)\\& = \int f(g,l+k)\,d\mu_0(g,l)=\int f(g,k)\,d\mu(g,l)=\langle \mu_k,f\rangle.\\[-43pt] \end{align*} $$
$$ \begin{align*} \langle \mu_0*\delta_{(0,k)},f\rangle&= \int \int f(g+h,l+n)\,d\mu_0(g,l)\,d\delta_{(0,k)}(h,n)\\& = \int f(g,l+k)\,d\mu_0(g,l)=\int f(g,k)\,d\mu(g,l)=\langle \mu_k,f\rangle.\\[-43pt] \end{align*} $$
 For each 
 $\mu $
 in
$\mu $
 in 
 $\mathcal M_c(G\times \mathbb {Z})$
, we define the measure
$\mathcal M_c(G\times \mathbb {Z})$
, we define the measure 
 $\mu _G$
 in
$\mu _G$
 in 
 $\mathcal M_c(G)$
 by
$\mathcal M_c(G)$
 by 
 $$ \begin{align*}\langle \mu_G,\varphi\rangle=\int \varphi(g)\,d\mu(g,l), \end{align*} $$
$$ \begin{align*}\langle \mu_G,\varphi\rangle=\int \varphi(g)\,d\mu(g,l), \end{align*} $$
whenever 
 $\varphi $
 is in
$\varphi $
 is in 
 $\mathcal C(G)$
. Clearly, every
$\mathcal C(G)$
. Clearly, every 
 $\varphi $
 in
$\varphi $
 in 
 $\mathcal C(G)$
 can be considered as a function in
$\mathcal C(G)$
 can be considered as a function in 
 $\mathcal C(G\times \mathbb {Z})$
, hence this definition makes sense, further we have
$\mathcal C(G\times \mathbb {Z})$
, hence this definition makes sense, further we have 
 $$ \begin{align*}\langle \mu_G,\varphi\rangle=\int \varphi(g)\,d\mu_0(g,l). \end{align*} $$
$$ \begin{align*}\langle \mu_G,\varphi\rangle=\int \varphi(g)\,d\mu_0(g,l). \end{align*} $$
Lemma 2. If I is a closed ideal in 
 $\mathcal M_c(G\times \mathbb {Z})$
, then the set
$\mathcal M_c(G\times \mathbb {Z})$
, then the set 
 $I_G$
 of all measures
$I_G$
 of all measures 
 $\mu _G$
 with
$\mu _G$
 with 
 $\mu $
 in I, is a closed ideal in
$\mu $
 in I, is a closed ideal in 
 $\mathcal M_c(G)$
.
$\mathcal M_c(G)$
.
Proof. Clearly 
 $\mu _G+\nu _G=(\mu +\nu )_G$
 and
$\mu _G+\nu _G=(\mu +\nu )_G$
 and 
 $\lambda \cdot \mu _G=(\lambda \cdot \mu )_G$
. Let
$\lambda \cdot \mu _G=(\lambda \cdot \mu )_G$
. Let 
 $\mu _G$
 be in I and
$\mu _G$
 be in I and 
 $\xi $
 in
$\xi $
 in 
 $\mathcal M_c(G)$
. Then we have for each
$\mathcal M_c(G)$
. Then we have for each 
 $\varphi $
 in
$\varphi $
 in 
 $\mathcal C(G)$
:
$\mathcal C(G)$
: 
 $$ \begin{align*} \langle \xi*\mu_G,\varphi\rangle=\int \int \varphi(g+h)\,d\xi(g)\,d\mu_G(h)=\int \int \varphi(g+h)\,d\xi(g)\,d\mu(h,l). \end{align*} $$
$$ \begin{align*} \langle \xi*\mu_G,\varphi\rangle=\int \int \varphi(g+h)\,d\xi(g)\,d\mu_G(h)=\int \int \varphi(g+h)\,d\xi(g)\,d\mu(h,l). \end{align*} $$
On the other hand, we extend 
 $\xi $
 from
$\xi $
 from 
 $\mathcal M_c(G)$
 to
$\mathcal M_c(G)$
 to 
 $\mathcal M_c(G\times \mathbb {Z})$
 by the definition
$\mathcal M_c(G\times \mathbb {Z})$
 by the definition 
 $$ \begin{align*} \langle \tilde{\xi},f\rangle=\int f(g,0)\,d\xi(g) \end{align*} $$
$$ \begin{align*} \langle \tilde{\xi},f\rangle=\int f(g,0)\,d\xi(g) \end{align*} $$
whenever f is in 
 $\mathcal C(G\times \mathbb {Z})$
. Then
$\mathcal C(G\times \mathbb {Z})$
. Then 
 $$ \begin{align*} \langle \tilde{\xi}_{G},\varphi\rangle=\int \varphi(g)\,d\tilde{\xi}_0(g,l)=\int \varphi(g)\,d\xi(g)=\langle \xi,\varphi\rangle, \end{align*} $$
$$ \begin{align*} \langle \tilde{\xi}_{G},\varphi\rangle=\int \varphi(g)\,d\tilde{\xi}_0(g,l)=\int \varphi(g)\,d\xi(g)=\langle \xi,\varphi\rangle, \end{align*} $$
that is 
 $\tilde {\xi }_{G}=\xi $
. Finally, a simple calculation shows that
$\tilde {\xi }_{G}=\xi $
. Finally, a simple calculation shows that 
 $$ \begin{align*} \langle \xi*\mu_G,\varphi\rangle=\langle (\tilde{\xi}*\mu)_G,\varphi\rangle, \end{align*} $$
$$ \begin{align*} \langle \xi*\mu_G,\varphi\rangle=\langle (\tilde{\xi}*\mu)_G,\varphi\rangle, \end{align*} $$
hence 
 $\xi *\mu _G=(\tilde {\xi }*\mu )_G$
 is in
$\xi *\mu _G=(\tilde {\xi }*\mu )_G$
 is in 
 $I_G$
, as
$I_G$
, as 
 $\tilde {\xi }*\mu $
 is in I.
$\tilde {\xi }*\mu $
 is in I.
 Now we show that the ideal 
 $I_G$
 is closed. Assume that
$I_G$
 is closed. Assume that 
 $(\mu _{\alpha })$
 is a generalized sequence in I such that the generalized sequence
$(\mu _{\alpha })$
 is a generalized sequence in I such that the generalized sequence 
 $(\mu _{{\alpha },G})$
 converges to
$(\mu _{{\alpha },G})$
 converges to 
 $\xi $
 in
$\xi $
 in 
 $\mathcal M_c(G)$
. This means that
$\mathcal M_c(G)$
. This means that 
 $$ \begin{align*} \lim_{\alpha} \int \varphi(g)\,d\mu_{{\alpha},G}(g)=\int \varphi(g)\,d\xi(g) \end{align*} $$
$$ \begin{align*} \lim_{\alpha} \int \varphi(g)\,d\mu_{{\alpha},G}(g)=\int \varphi(g)\,d\xi(g) \end{align*} $$
holds for each 
 $\varphi $
 in
$\varphi $
 in 
 $\mathcal C(G)$
. In particular, for each exponential m on G we have
$\mathcal C(G)$
. In particular, for each exponential m on G we have 

In other words,
 $$ \begin{align*} \lim_{\alpha} \widehat{\mu}_{{\alpha},0}=\widehat{\tilde{\xi}}_0 \end{align*} $$
$$ \begin{align*} \lim_{\alpha} \widehat{\mu}_{{\alpha},0}=\widehat{\tilde{\xi}}_0 \end{align*} $$
holds. It follows
 $$ \begin{align*} \lim_{\alpha} \mu_{i,0}=\tilde{\xi}_0, \end{align*} $$
$$ \begin{align*} \lim_{\alpha} \mu_{i,0}=\tilde{\xi}_0, \end{align*} $$
consequently
 $$ \begin{align*} \tilde{\xi}_k=\tilde{\xi}_0*\delta_{(0,k)}=\lim_{\alpha} \mu_{{\alpha},0}*\delta_{(0,k)}=\lim_{\alpha} \mu_{{\alpha},k}. \end{align*} $$
$$ \begin{align*} \tilde{\xi}_k=\tilde{\xi}_0*\delta_{(0,k)}=\lim_{\alpha} \mu_{{\alpha},0}*\delta_{(0,k)}=\lim_{\alpha} \mu_{{\alpha},k}. \end{align*} $$
Then we infer
 $$ \begin{align*} \tilde{\xi}=\sum_k \tilde{\xi}_k=\sum_k \lim_{\alpha} \mu_{{\alpha},k}=\lim_{\alpha} \sum_k \mu_{{\alpha},k}=\lim_{\alpha} \mu_{\alpha}, \end{align*} $$
$$ \begin{align*} \tilde{\xi}=\sum_k \tilde{\xi}_k=\sum_k \lim_{\alpha} \mu_{{\alpha},k}=\lim_{\alpha} \sum_k \mu_{{\alpha},k}=\lim_{\alpha} \mu_{\alpha}, \end{align*} $$
where we can interchange the sum and the limit using the fact that in each sum the number of nonzero terms is finite. As I is closed, 
 $\tilde {\xi }$
 is in I, which proves that
$\tilde {\xi }$
 is in I, which proves that 
 ${\xi }=\tilde {\xi }_{G}$
 is in
${\xi }=\tilde {\xi }_{G}$
 is in 
 $I_G$
, that is,
$I_G$
, that is, 
 $I_G$
 is closed.
$I_G$
 is closed.
Now we can derive the following theorem.
Theorem 4. Let G be a locally compact Abelian group. Then spectral synthesis holds on G if and only if it holds on 
 $G\times \mathbb {Z}$
.
$G\times \mathbb {Z}$
.
Proof. If spectral synthesis holds on 
 $G\times \mathbb{Z}$
, then it obviously holds on its continuous homomorphic images, in particular, it holds on G, which is the projection of
$G\times \mathbb{Z}$
, then it obviously holds on its continuous homomorphic images, in particular, it holds on G, which is the projection of 
 $G\times \mathbb {Z}$
 onto the first component.
$G\times \mathbb {Z}$
 onto the first component.
 Conversely, we assume that spectral synthesis holds on G. This means that every closed ideal in the Fourier algebra of G is localizable, and we need to show the same for all closed ideals of the Fourier algebra of 
 $G\times \mathbb {Z}$
.
$G\times \mathbb {Z}$
.
 We consider the closed ideal 
 $\widehat {I}$
 in the Fourier algebra
$\widehat {I}$
 in the Fourier algebra 
 $\mathcal A(G\times \mathbb {Z})$
, and we assume that
$\mathcal A(G\times \mathbb {Z})$
, and we assume that 
 $\widehat {I}$
 is nonlocalizable, that is, there is a measure
$\widehat {I}$
 is nonlocalizable, that is, there is a measure 
 $\nu $
 in
$\nu $
 in 
 $\mathcal M_c(G\times \mathbb {Z})$
 such that
$\mathcal M_c(G\times \mathbb {Z})$
 such that 
 $\widehat {\nu }$
 is annihilated by
$\widehat {\nu }$
 is annihilated by 
 $\mathcal P_{\widehat {I},m,\lambda }$
 for each m and
$\mathcal P_{\widehat {I},m,\lambda }$
 for each m and 
 $\lambda $
, but
$\lambda $
, but 
 $\widehat {\nu }$
 is not in
$\widehat {\nu }$
 is not in 
 $\widehat {I}$
. We show that
$\widehat {I}$
. We show that 
 $\widehat {\nu }_G$
 is in
$\widehat {\nu }_G$
 is in 
 $\widehat {I}_G$
; then it will follow that
$\widehat {I}_G$
; then it will follow that 
 $\widehat {\nu }$
 is in
$\widehat {\nu }$
 is in 
 $\widehat {I}$
, a contradiction.
$\widehat {I}$
, a contradiction.
 Suppose that a polynomial derivation d annihilates 
 $\widehat {I}_G$
 at m. Then we have
$\widehat {I}_G$
 at m. Then we have 

for each 
 $\widehat {\mu }$
 in
$\widehat {\mu }$
 in 
 $\widehat {I}_G$
 and for every exponential m on G, where
$\widehat {I}_G$
 and for every exponential m on G, where 
 $p_{d,m}:G\to \mathbb {C}$
 is the generating polynomial of d at m. Then we define the polynomial derivation D on the Fourier algebra
$p_{d,m}:G\to \mathbb {C}$
 is the generating polynomial of d at m. Then we define the polynomial derivation D on the Fourier algebra 
 $\mathcal A(G\times \mathbb {Z})$
 by
$\mathcal A(G\times \mathbb {Z})$
 by 

If 
 $\widehat {\mu }$
 is in
$\widehat {\mu }$
 is in 
 $\widehat {I}$
, then we have
$\widehat {I}$
, then we have 

for each k in 
 $\mathbb {Z}$
. As
$\mathbb {Z}$
. As 
 $\widehat {\mu }=\sum _{k\in \mathbb {Z}} \widehat {\mu }_k$
, it follows that
$\widehat {\mu }=\sum _{k\in \mathbb {Z}} \widehat {\mu }_k$
, it follows that 
 $D\widehat {\mu }(m,\lambda )=0$
 for each
$D\widehat {\mu }(m,\lambda )=0$
 for each 
 $\widehat {\mu }$
 in
$\widehat {\mu }$
 in 
 $\widehat {I}$
. In other words, D is in
$\widehat {I}$
. In other words, D is in 
 $\mathcal P_{\widehat {I},m,\lambda }$
 for each exponential m and nonzero complex number
$\mathcal P_{\widehat {I},m,\lambda }$
 for each exponential m and nonzero complex number 
 $\lambda $
. In particular,
$\lambda $
. In particular, 
 $\widehat {\nu }$
 is annihilated by D:
$\widehat {\nu }$
 is annihilated by D: 

It follows

As d is an arbitrary polynomial derivation which annihilates 
 $\widehat {I}_G$
 at m, we have that
$\widehat {I}_G$
 at m, we have that 
 $\widehat {\nu }_G$
 is annihilated by
$\widehat {\nu }_G$
 is annihilated by 
 $\mathcal P_{\widehat {I}_G,m}$
 for each m. As spectral synthesis holds on G, the ideal
$\mathcal P_{\widehat {I}_G,m}$
 for each m. As spectral synthesis holds on G, the ideal 
 $\widehat {I}_G$
 is localizable, consequently
$\widehat {I}_G$
 is localizable, consequently 
 $\widehat {\nu }_G$
 is in
$\widehat {\nu }_G$
 is in 
 $\widehat {I}_G$
, which implies that
$\widehat {I}_G$
, which implies that 
 $\widehat {\nu }$
 is in
$\widehat {\nu }$
 is in 
 $\widehat {I}$
, and our theorem is proved.
$\widehat {I}$
, and our theorem is proved.
6 Characterization theorems
Corollary 3. Let G be a compactly generated locally compact Abelian group. Then spectral synthesis holds on G if and only if G is topologically isomorphic to 
 $\mathbb {R}^a\times \mathbb {Z}^b\times F$
, where
$\mathbb {R}^a\times \mathbb {Z}^b\times F$
, where 
 $a\leq 1$
 and b are nonnegative integers, and F is an arbitrary compact Abelian group.
$a\leq 1$
 and b are nonnegative integers, and F is an arbitrary compact Abelian group.
Proof. By the Structure Theorem of compactly generated locally compact Abelian groups (see [Reference Hewitt and Ross3, (9.8) Theorem]) G is topologically isomorphic to 
 $ \mathbb {R}^a\times \mathbb {Z}^b\times F, $
 where
$ \mathbb {R}^a\times \mathbb {Z}^b\times F, $
 where 
 $a,b$
 are nonnegative integers, and F is a compact Abelian group. If spectral synthesis holds on G, then it holds on its projection
$a,b$
 are nonnegative integers, and F is a compact Abelian group. If spectral synthesis holds on G, then it holds on its projection 
 $\mathbb {R}^a$
. By the results in [Reference Schwartz1, Reference Gurevič6], spectral synthesis holds on
$\mathbb {R}^a$
. By the results in [Reference Schwartz1, Reference Gurevič6], spectral synthesis holds on 
 $\mathbb {R}^a$
 if and only if
$\mathbb {R}^a$
 if and only if 
 $a\leq 1$
, hence G is topologically isomorphic to
$a\leq 1$
, hence G is topologically isomorphic to 
 $\mathbb {R}^a\times \mathbb {Z}^b\times F$
 where
$\mathbb {R}^a\times \mathbb {Z}^b\times F$
 where 
 $a\leq 1$
 and b are nonnegative integers, and F is a compact Abelian group.
$a\leq 1$
 and b are nonnegative integers, and F is a compact Abelian group.
 Conversely, let 
 $G=\mathbb {R}\times \mathbb {Z}^b\times F$
 with b a nonnegative integer, and F a compact Abelian group. By [Reference Schwartz1], spectral synthesis holds on
$G=\mathbb {R}\times \mathbb {Z}^b\times F$
 with b a nonnegative integer, and F a compact Abelian group. By [Reference Schwartz1], spectral synthesis holds on 
 $\mathbb {R}$
. By repeated application of Theorem 4, we have that spectral synthesis holds on
$\mathbb {R}$
. By repeated application of Theorem 4, we have that spectral synthesis holds on 
 $\mathbb {R}\times \mathbb {Z}^b$
 with any nonnegative integer b. Finally, by Theorem 3, spectral synthesis holds on
$\mathbb {R}\times \mathbb {Z}^b$
 with any nonnegative integer b. Finally, by Theorem 3, spectral synthesis holds on 
 $\mathbb {R}\times \mathbb {Z}^b\times F$
. Our proof is complete.
$\mathbb {R}\times \mathbb {Z}^b\times F$
. Our proof is complete.
Corollary 4. Let G be a locally compact Abelian group. Let B denote the closed subgroup of all compact elements in G. Then spectral synthesis holds on G if and only if 
 $G/B$
 is topologically isomorphic to
$G/B$
 is topologically isomorphic to 
 $\mathbb {R}^n\times F$
, where
$\mathbb {R}^n\times F$
, where 
 $n\leq 1$
 is a nonnegative integer, and F is a discrete torsion free Abelian group of finite rank.
$n\leq 1$
 is a nonnegative integer, and F is a discrete torsion free Abelian group of finite rank.
Proof. First we prove the necessity. If spectral synthesis holds on G, then it holds on 
 $G/B$
. By [Reference Hewitt and Ross3, (24.34) Theorem],
$G/B$
. By [Reference Hewitt and Ross3, (24.34) Theorem], 
 $G/B$
 has sufficiently enough real characters. By [Reference Hewitt and Ross3, (24.35) Corollary],
$G/B$
 has sufficiently enough real characters. By [Reference Hewitt and Ross3, (24.35) Corollary], 
 $G/B$
 is topologically isomorphic to
$G/B$
 is topologically isomorphic to 
 $\mathbb {R}^n\times F$
, where n is a nonnegative integer, and F is a discrete torsion-free Abelian group. As spectral synthesis holds on
$\mathbb {R}^n\times F$
, where n is a nonnegative integer, and F is a discrete torsion-free Abelian group. As spectral synthesis holds on 
 $\mathbb {R}^n\times F$
, it holds on the continuous projections
$\mathbb {R}^n\times F$
, it holds on the continuous projections 
 $\mathbb {R}^n$
 and F. Then we have
$\mathbb {R}^n$
 and F. Then we have 
 $n\leq 1$
, and the torsion-free rank of F is finite, by [Reference Laczkovich and Székelyhidi8].
$n\leq 1$
, and the torsion-free rank of F is finite, by [Reference Laczkovich and Székelyhidi8].
 For the sufficiency, if F is a torsion-free discrete Abelian group with finite rank, then it is the (continuous) homomorphic image of 
 $\mathbb {Z}^k$
 with some nonnegative integer k. By repeated application of Theorem 4, we have that spectral synthesis holds on
$\mathbb {Z}^k$
 with some nonnegative integer k. By repeated application of Theorem 4, we have that spectral synthesis holds on 
 $\mathbb {R}\times \mathbb {Z}^k$
, and then it holds on its continuous homomorphic image
$\mathbb {R}\times \mathbb {Z}^k$
, and then it holds on its continuous homomorphic image 
 $\mathbb {R}\times F$
. Finally, by Theorem 3, we have that spectral synthesis holds on G.
$\mathbb {R}\times F$
. Finally, by Theorem 3, we have that spectral synthesis holds on G.
Acknowledgements
The research was supported by the Hungarian National Foundation for Scientific Research (OTKA), Grant No. K-134191.
Competing interest
The author has no competing interests to declare.
Financial support
None.
 
  
