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Credibility excess as an epistemic injustice

Published online by Cambridge University Press:  27 January 2025

Keith Dyck*
Affiliation:
Philosophy, UC Santa Barbara, Santa Barbara, CA, USA
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Abstract

According to Fricker’s (2007) seminal account, an epistemic injustice is done when, based on prejudice, a hearer ascribes to a speaker a level of credibility below what they deserve. When prejudice results in credibility excess, however, Fricker contends no similar injustice takes place. In this paper, I will challenge the second of these claims. Using a modified version of Zollman’s (2007) two-armed bandit model, I will show how the systematic over-ascription of credibility within a dominant group can produce epistemic advantages for that group relative to non-group members.

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Type
Article
Creative Commons
Creative Common License - CCCreative Common License - BY
This is an Open Access article, distributed under the terms of the Creative Commons Attribution licence (https://creativecommons.org/licenses/by/4.0/), which permits unrestricted re-use, distribution and reproduction, provided the original article is properly cited.
Copyright
© The Author(s), 2025. Published by Cambridge University Press
Figure 0

Figure 1. Distributions of actual successes, reported successes, and successes assumed by an updating agent, when n=150$n = 150$, ε=0.3$\varepsilon = 0.3$, r=0.6$r = 0.6$, and c=0.8$c = 0.8$.

Figure 1

Figure 2. Fraction of simulations reaching correct consensus over a range of cdominant${c_{dominant}}$ and f$f$ values, when N=12$N = 12$, n=10$n = 10$, and ε=0.01$\varepsilon = 0.01$.

Figure 2

Figure 3. Average rounds to 0.99$0.99$ credence for agents in the dominant and marginalized groups over a range of cdominant${c_{dominant}}$ values, when N=24$N = 24$, f=12$f = {1 \over 2}$, n=1$n = 1$, and ε=0.02$\varepsilon = 0.02$.

Figure 3

Figure 4. Average credence for agents in the dominant and marginalized groups over a range of cdominant${c_{dominant}}$ values, when N=48$N = 48$, f=112$f = {1 \over {12}}$, n=1$n = 1$, and ε=0.05$\varepsilon = 0.05$.