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Convective plumes in rotating systems

Published online by Cambridge University Press:  21 June 2016

Bruno Deremble*
Affiliation:
Department of Earth, Ocean and Atmospheric Sciences, The Florida State University, Tallahassee, FL 32306-4520, USA
*
Email address for correspondence: bderemble@fsu.edu

Abstract

Convective plumes emanating from fixed buoyant sources such as volcanoes, hot springs and oil spills are common in the atmosphere and the ocean. Most of what we know about their dynamics comes from scaling laws, laboratory experiments and numerical simulations. A plume grows laterally during its ascent mainly due to the process of turbulent entrainment of fluid from the environment into the plume. In an unstratified system, nothing hampers the vertical motion of the plume. By contrast, in a stratified system, as the plume rises, it reaches and overshoots the neutral buoyancy height – due to the non-zero momentum at that height. This rising fluid is then dense relative to the environment and slows down, ceases to rise and falls back to the height of the intrusion. For buoyant plumes occurring in the ocean or atmosphere, the rotation of the Earth adds an additional constraint via the conservation of angular momentum. In fact, the effect of rotation is still not well understood, and we addressed this issue in the study reported here. We looked for the steady states of an axisymmetric model in both the rotating and non-rotating cases. At the non-rotating limit, we isolated two regimes of convection depending on the buoyancy flux/momentum flux ratio at the base of the plume, in agreement with scaling laws. However, the inclusion of rotation in the model strongly affects these classical convection patterns: the lateral extension of the plume is confined at the intrusion level by the establishment of a geostrophic balance, and non-trivial swirl speed develops in and around the plume.

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Papers
Creative Commons
Creative Common License - CCCreative Common License - BY
This is an Open Access article, distributed under the terms of the Creative Commons Attribution licence (http://creativecommons.org/licenses/by/4.0/), which permits unrestricted re-use, distribution, and reproduction in any medium, provided the original work is properly cited.
Copyright
© 2016 Cambridge University Press
Figure 0

Figure 1. The levels $H_{b}$ (green with circles) and $H_{w}$ (blue with crosses) as a function of the buoyancy flux $F_{0}$ in non-dimensional units. The black line is the scaling law (2.13). The blue dashed line (slope $=$ 0) is (A 11) and the green dashed line (slope $=$ 1) is (A 4).

Figure 1

Table 1. Boundary conditions for the system of (3.8).

Figure 2

Figure 2. (a) Stream function ${\it\psi}$ and (b) temperature $T$ of a typical steady state for $F_{0}=0.1$. The levels $H_{w}$ and $H_{b}$ (green dotted lines) are computed in the axisymmetric model at the first grid point and $r=0$ respectively (see next section for details). The level $H_{i}$ (green dotted line) is computed at $r=1$. The contour interval is $5\times 10^{-4}$ in (a) and $1.0$ in (b). Negative contours are plotted with dashed lines. The thick red line in (b) is a contour level of a passive tracer released at the source of the plume and advected with the flow shown in (a). The passive tracer reaches $r=1$ at $t=28$. The thick blue line in (a) is $R(z)$ computed with the original MTT model (2.5).

Figure 3

Figure 3. The levels $H_{w}$ (blue with crosses) and $H_{b}$ (green with circles) in the axisymmetric model (solid lines) and in MTT’s model (dashed lines). The solid black line is $F_{0}^{1/4}$. The level $H_{i}$ in the axisymmetric model (red line) is slightly above, but almost indistinguishable from, the green line ($H_{b}$). The buoyancy flux $F_{0}$ varies via the bottom boundary condition $T_{0}$. The parameters at the inlet are $w_{0}=0.1$ and $R_{0}=0.02$.

Figure 4

Figure 4. Steady state for $Ro=20$ and $F_{0}=0.1$. (a) Stream function, ${\it\psi}$, (b) temperature (black), $T$, envelope of the plume from the time integration of a passive tracer (thick red), (c) angular momentum, ${\it\lambda}$, (d) swirl velocity (shaded area is negative), $v$. The passive tracer reaches $r=1$ at $t=55\;(\simeq 3f^{-1})$.

Figure 5

Figure 5. The same as figure 4(a,b) but with $Ro=0.4$. For this configuration, $R_{d}=0.27$ and is marked with a dotted green line. The envelope of the passive tracer is shown at two different time intervals, $t=55$ ($\simeq \,137f^{-1}$) (solid red line) and $t=1450$ ($\simeq \,3625f^{-1}$) (dashed red line).

Figure 6

Figure 6. Bifurcation diagram ($\overline{w}$ as a function of $l_{s}$) in the non-rotating (black curve with stars) and rotating cases (red curve with crosses). Here, $S_{1}$ and $S_{2}$ mark the positions of the two saddle-node bifurcations. All of these steady states are stable except between $S_{1}$ and $S_{2}$.

Figure 7

Figure 7. Bifurcation diagram ($\overline{w}$ as a function of $C_{b}$) for the rotating case only. In contrast to figure 6, this figure reads from left to right.

Figure 8

Figure 8. Typical steady state in the centrifugal branch ($l_{s}=0.003$). (a) Stream function, ${\it\psi}$, (b) temperature (black), $T$, and envelope of passive tracer obtained with a time integration (red). The passive tracer reaches $r=1$ at $t=78$ ($\simeq \,4f^{-1}$). This plot is very similar to the solution found at $C_{b}=1$.

Figure 9

Figure 9. The position of the cusp bifurcation, ${\it\Gamma}_{0}^{c}$, as a function of $Ro$. The grey area is the region where multiple steady states coexist.

Figure 10

Figure 10. Vertical cross-section in the middle of the domain showing two time averages of the vertical velocity for two distinct periods: (a) early stage ($0) and (b) mature stage ($4f^{-1}), shown in dimensional units (m for the axis and m s$^{-1}$ for the colour bar). To highlight negative velocities, the colour scales do not extend over all positive values.

Figure 11

Figure 11. The level $H_{w}$ as a function of the stratification $N$ in non-dimensional units. The blue line with crosses is the numerical value obtained using (2.11), when solving (2.5). The solid black line is (A 10) and the red dashed line is (A 11). We used $F_{0}=2\times 10^{-8}$, $w_{0}=1$ and $R_{0}=0.02$.